JEE Physics Intermediate Topics
Rotational Mechanics (High Importance)
KEY CONCEPTS:
Moment of Inertia (I): I = Σmr² (discrete) | I = ∫r²dm (continuous)
Standard MI values:
Solid sphere about diameter: I = 2mr²/5
Hollow sphere about diameter: I = 2mr²/3
Solid cylinder about axis: I = mr²/2
Thin ring about axis: I = mr²
Rod about centre: I = mL²/12 | about end: I = mL²/3
Parallel axis theorem: I = Icm + md²
Perpendicular axis theorem (lamina): Iz = Ix + Iy
Torque: τ = r × F = Iα
Angular momentum: L = Iω | dL/dt = τ
Conservation of L: when τ_external = 0
ROLLING MOTION:
Rolling without slipping: v = rω (constraint)
Total KE = Translational KE + Rotational KE
= ½mv² + ½Iω² = ½mv²(1 + I/mr²)
Acceleration on incline:
a = g sinθ / (1 + I/mr²)
Ring < Cylinder < Sphere (least a to most a, i.e., ring slowest down incline)
TYPICAL PROBLEMS:
Toppling condition: normal force moves to edge when CG tilts beyond base
Angular impulse: J = τ·Δt = ΔL (analogous to linear impulse)
Electromagnetic Induction
FARADAY'S LAW: EMF = -dΦ/dt where Φ = B·A·cos θ (flux)
LENZ'S LAW: induced current opposes the change in flux
MOTIONAL EMF: ε = BLv (rod of length L moving at velocity v in field B)
SELF INDUCTANCE: L = NΦ/I | ε = -L dI/dt
Inductor energy: U = ½LI²
RL CIRCUIT:
Growth: I = (V/R)(1 - e^(-t/τ)) where τ = L/R
Decay: I = I₀e^(-t/τ)
AC CIRCUITS:
XL = ωL | XC = 1/(ωC) | Z = √(R² + (XL-XC)²)
Power: P = VrmsIrms cos φ where cos φ = R/Z (power factor)
Resonance: XL = XC → ω₀ = 1/√(LC) → Z = R (minimum, purely resistive)
At resonance: current maximum, power maximum, voltage across L and C can exceed supply
Study Resources
•DC Pandey Electricity and Magnetism — for class 12 topics, excellent problems
•HC Verma Exercise problems — all must be solved (use solutions for guidance)
•JEE Advanced PYQ — 2010-2024, difficulty level guide
•NPTEL Physics — IIT Kharagpur free lecture series