Light — Reflection and Refraction
Why This Chapter Matters
Light chapter is one of the highest-scoring in Class 10 Physics — 10-14 marks in board exams. Mirror formula, lens formula, power of lens, and ray diagrams are tested every year. Numerical problems are essential.
Prerequisites
Core Concepts
1. Reflection of Light
Laws of Reflection:
Terms:
2. Spherical Mirrors
Types:
Key terms:
Sign convention (New Cartesian):
3. Mirror Formula
$$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$$
Magnification:
$$m = \frac{-v}{u} = \frac{h_i}{h_o}$$
4. Image Formation by Concave Mirror
| Object Position | Image Position | Nature | Size |
|---|
|---|---|---|---|
| At infinity | At F | Real, inverted | Point/highly diminished |
|---|---|---|---|
| Beyond C | Between F and C | Real, inverted | Diminished |
| At C | At C | Real, inverted | Same size |
| Between C and F | Beyond C | Real, inverted | Enlarged |
| At F | At infinity | Real, inverted | Highly enlarged |
| Between P and F | Behind mirror | Virtual, erect | Enlarged |
Convex mirror: Always forms virtual, erect, diminished image behind mirror (regardless of object position) — that's why used as rear-view mirror (wider field of view).
5. Refraction of Light
Refraction: Bending of light as it passes from one medium to another.
Cause: Change in speed of light in different media.
Laws of Refraction:
Refractive index (n):
$$n = \frac{\text{Speed of light in vacuum (c)}}{\text{Speed of light in medium (v)}} = \frac{c}{v}$$
Light bends TOWARDS normal when entering denser medium, AWAY from normal when entering rarer medium.
6. Lenses
Convex (converging) lens: Thicker in middle, converges parallel rays to a focal point.
Concave (diverging) lens: Thinner in middle, diverges parallel rays.
7. Lens Formula
$$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$$
Magnification for lens:
$$m = \frac{v}{u}$$
8. Power of Lens
$$P = \frac{1}{f}$$
9. Image Formation by Convex Lens
| Object Position | Image | Nature | Size |
|---|
|---|---|---|---|
| At infinity | At F₂ | Real, inverted | Point |
|---|---|---|---|
| Beyond 2F₁ | Between F₂ and 2F₂ | Real, inverted | Diminished |
| At 2F₁ | At 2F₂ | Real, inverted | Same size |
| Between 2F₁ and F₁ | Beyond 2F₂ | Real, inverted | Enlarged |
| At F₁ | At infinity | Real, inverted | Very large |
| Between F₁ and O | Same side as object | Virtual, erect | Enlarged |
Solved Examples
Example 1 — Mirror Formula
Q: An object is placed at 30 cm from a concave mirror of focal length 15 cm. Find image position.
u = −30 cm, f = −15 cm (concave mirror)
1/v + 1/u = 1/f
1/v + 1/(−30) = 1/(−15)
1/v = −1/15 + 1/30 = −2/30 + 1/30 = −1/30
v = −30 cm (real, in front of mirror)
Magnification: m = −v/u = −(−30)/(−30) = −1 (same size, inverted, real)
Example 2 — Power of Lens
Q: A lens has focal length +50 cm. What is its power?
f = +50 cm = +0.5 m
P = 1/f = 1/0.5 = +2 D (converging lens)
PYQs
2023
Q: An object is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Find image distance and magnification.
u = −15 cm, f = +10 cm
1/v − 1/u = 1/f
1/v − 1/(−15) = 1/10
1/v = 1/10 − 1/15 = 3/30 − 2/30 = 1/30
v = +30 cm (real, inverted, on other side)
m = v/u = 30/(−15) = −2 (inverted, twice the size)
2022
Q: Why does a ray of light bend when it travels from one medium to another?
Light travels at different speeds in different media. When light enters a denser medium (glass from air), it slows down and bends towards the normal. When entering a rarer medium, it speeds up and bends away from the normal.
2021
Q: Define focal length of a concave mirror. What is the relationship between focal length and radius of curvature?
Focal length = distance between pole and principal focus of mirror.
Relationship: f = R/2 (focal length is half the radius of curvature).
MCQ Practice
Q1. Which mirror is used as a rear-view mirror in vehicles?
(A) Plane (B) Concave (C) Convex ✓ (D) Cylindrical
[Convex — provides wider field of view]
Q2. Power of a concave lens is:
(A) Positive (B) Zero (C) Negative ✓ (D) Infinite
[Concave = diverging = negative focal length = negative power]
Q3 (Hard). Object placed 20 cm from concave mirror, image 30 cm behind mirror. Focal length?
u = −20 cm, v = +30 cm (behind mirror → virtual → positive)
1/f = 1/v + 1/u = 1/30 + 1/(−20) = 2/60 − 3/60 = −1/60
f = −60 cm (concave mirror → focal length negative)
Revision Notes
Common Mistakes:
❌ Mirror formula same as lens formula — they're DIFFERENT (check signs)
❌ Forgetting to use metres in power calculation (P = 1/f requires f in metres)
❌ Convex mirror always forms virtual image — but forgetting it's also always diminished and erect

