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JEE ChemistryPractice Q&A

Practice questions and model answers

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Verified by practitioners with 5+ years production experience· Updated 2025 · SynfraCore JEE Chemistry Team
Expert Content

JEE Chemistry — Important Questions & Concepts

Physical Chemistry

Q: Molarity vs molality — when to use each?

Molarity (M) = moles of solute / litres of solution
  Changes with temperature (volume expands/contracts)
  Used for: dilutions, titrations, stoichiometry

Molality (m) = moles of solute / kg of solvent
  Temperature independent (mass doesn't change)
  Used for: colligative properties (ΔTf, ΔTb, osmotic pressure)

Q: Rate of reaction: 2NO + O₂ → 2NO₂. Write rate expression.

Rate = k[NO]²[O₂]
  NO is second order (exponent = 2 from balanced equation for elementary)
  O₂ is first order
  Overall order = 3
Note: Order from equation only valid for elementary reactions
       For complex reactions, order determined experimentally

Q: Calculate ΔG° for reaction with Kp = 10⁵ at 300K.

ΔG° = -RT ln Kp = -8.314 × 300 × ln(10⁵)
     = -2494.2 × 5 × 2.303
     = -28,722 J/mol ≈ -28.7 kJ/mol
Negative ΔG° → spontaneous reaction (Kp > 1 → products favoured)

Organic Chemistry

Q: Explain SN1 vs SN2 mechanisms.

SN1 (Substitution Nucleophilic Unimolecular):
  2 steps: ionisation → carbocation intermediate
  Rate = k[substrate] (first order — only substrate in slow step)
  Favoured: tertiary > secondary substrates
           Polar protic solvents (water, alcohol)
           Weak nucleophiles
  Stereochemistry: racemisation (carbocation attacked from both sides)

SN2 (Bimolecular):
  1 step: nucleophile attacks as leaving group leaves (backside attack)
  Rate = k[substrate][nucleophile] (second order)
  Favoured: primary > secondary substrates (less steric hindrance)
           Polar aprotic solvents (DMSO, acetone)
           Strong nucleophiles
  Stereochemistry: inversion (Walden inversion)

Inorganic Chemistry

Q: Why is the second ionisation energy of Na very high?

Na (Z=11): 1s² 2s² 2p⁶ 3s¹
First IE: remove 3s¹ electron (outermost, easiest) → Na⁺ = noble gas config
Second IE: remove electron from 2p⁶ (inner shell, full shell, much harder)
IE₂ >> IE₁ because noble gas configuration is highly stable

Revision Notes

MOLE CONCEPT: n = mass/molar mass | PV = nRT | 1 mol = 6.022×10²³
SOLUTIONS:
  Molarity (M): moles/litres | Molality (m): moles/kg solvent
  Normality (N) = n × M (n = equivalents)
  Henry's law: p = KH·x | Raoult's law: P_total = x_A·P_A° + x_B·P_B°

KINETICS: rate = k[A]^m[B]^n | t½ for 1st order = 0.693/k
THERMOCHEMISTRY: ΔG = ΔH - TΔS | ΔG° = -RT lnK
  ΔG < 0: spontaneous | ΔG > 0: non-spontaneous

ORGANIC MECHANISMS:
  SN1: tertiary, racemisation, protic solvent
  SN2: primary, inversion, aprotic solvent, strong nucleophile
  E1: tertiary, carbocation, Zaitsev product
  E2: secondary/tertiary, strong base, anti-periplanar
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